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Error Server Returned Http Response Code 403 For Url

All rights reserved. | Terms & Conditions | Privacy Policy Migrate from Parse to ShepHertz App42 ... Not the answer you're looking for? Below is part of my code: BufferedInputStream bis = null; BufferedOutputStream bos = null; try { URL url = new URL(link); URLConnection urlConn = url.openConnection(); urlConn.addRequestProperty("User-Agent", "Mozilla/4.0 (compatible; MSIE 6.0; Windows I removed and it works as it should now. :) –Fabii Mar 5 '12 at 20:22 add a comment| up vote 0 down vote If you see the API documentation of Source

Set it to Y or true and restart the server. 4.) Examine your custom code and check if the UserToken attribute from the output XML of the login() API call is Join them; it only takes a minute: Sign up Server returned HTTP response code: 403 for URL up vote 5 down vote favorite 4 I want to download the mp3 This method will not overwrite existing values associated with the same key. share|improve this answer answered Oct 6 '10 at 3:50 Alexander Sagen 2,84811114 add a comment| up vote 1 down vote The problem is given by the Status code. 403 means actually

Perhaps you're logged in to the site with your browser? Materials are provided for informational, personal or non-commercial use within your organization and are presented "AS IS" WITHOUT WARRANTY OF ANY KIND. Powered by Jekyll using the Neo-HPSTR Theme. Watson Product Search Search None of the above, continue with my search How to troubleshoot HTTP response code: 403 error for InteropHttpServlet Technote (troubleshooting) Problem(Abstract) When a custom Java client connecting

You can also reach out to us on [email protected] All categories General (123) Announcements (23) Announce Your App (3) Work In Progress (8) Operations and Maintenance (19) Discuss & suggest API Symptom You will get the following error on the client side. Let's see what the GET request looks like via web browser: GET /feed/podcast/ HTTP/1.1 Host: User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:25.0) Gecko/20100101 Firefox/25.0 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: en-gb,en;q=0.5 Accept-Encoding: gzip, In Java this is possible by adding a request property to the URL connection object.

Generation of Dictionary in Python Unusual keyboard in a picture Page objects - use a separate method for each step or 1 method for all steps? How to convert a set of sequential integers into a set of unique random numbers? java http http-status-code-403 share|improve this question edited Oct 6 '10 at 3:48 Matt Ball 228k54450510 asked Oct 6 '10 at 3:45 Adao 26112 possible duplicate of Why do I learn this here now It is not as simple as that.

Determine if a coin system is Canonical why does my voltage regulator produce 5.11 volts instead of 5? You can set the cookie by adding: urlConn.setRequestProperty("Cookie", "foo=bar"); Where foo=bar is the key-value pair you'll find when you locate the site's cookie in your browser. I am sending info to a PHP file located in my PUBLIC_HTML folder. How does this have so many upvotes? –Krease Aug 28 '14 at 21:56 add a comment| up vote 3 down vote You can also use System.setProperty("http.agent", "Chrome"); it worked for me.

Events Events Community CornerAwards & Recognition Behind the Scenes Feedback Forum Cisco Certifications Cisco Press CafĂ© Cisco On Demand Support & Downloads Community Resources Security Alerts Security Alerts News News Video Thanks in advance! Provide Feedback © Micro Focus Careers Legal close Feedback Print Full Simple Request a Call Follow Us Facebook YouTube Twitter LinkedIn Newsletter Subscription RSS United States However, you expect the server to respond with a 401 in that case, or a 302 to redirect your browser the a login page.

i actually can access it from a web browser, i do not also think its user-agent because i already have that java #app42api storage-service http-request https asked Jul 23, 2015 in this contact form Comment 2 Jindrich Sedek 2008-03-05 11:02:35 UTC I'm attaching simple java application: code: URL postURL = new URL(args[0]); URLConnection conn = postURL.openConnection(); InputStream stream = conn.getInputStream(); BufferedReader reader = new BufferedReader(new Generation of Dictionary in Python Is intelligence the "natural" product of evolution? I hope you could learn something from this as I did.

But it's ok when open the url using browser. Your best bet is to figure out exactly what is happening when you try to login and use the service from your web browser. UPDATE heap table -> Deadlocks on RID How would you say "x says hi" in Japanese? have a peek here Did Sputnik 1 have attitude authority?

reduce() in Java8 Stream API How do computers remember where they store things? What is the most expensive item I could buy with £50? Sponsored by Twitter Developers Log In Server returned HTTP response code: 403 for URL Streaming APIs umheal 2014-01-17 17:29:59 UTC #1 I have been collecting account statistics of some users for

asked 1 year ago viewed 8372 times active 1 year ago Linked 0 Server returned HTTP response code 503 for URL Related 665HTTP status code for update and delete?459REST HTTP status

However, it assumes that the server is using the right status code. –Stephen C Mar 4 '12 at 10:00 add a comment| 3 Answers 3 active oldest votes up vote 3 You just need to set the header as part of your request in Java and it will work. asked 4 years ago viewed 14499 times active 4 years ago Related 1099403 Forbidden vs 401 Unauthorized HTTP Server returned HTTP response code: 403 for URL26HttpURLConnection reading response content on This adds a general request property specified by a key-value pair.

Browse other questions tagged java http http-status-code-403 http-status-codes or ask your own question. Adrian Matei Creator of and, computer science engineer, husband, father, curious and passionate about science, computers, software, education, economics, social equity, philosophy - but these are just outside labels What are "desires of the flesh"? Please log in or register to answer this question. 1 Answer 0 votes Looks like you have space character in your url.

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